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3 years ago

Write the point slope form of the equation of the line through the given slope through (5,3) ,slope =-1/5

Mathematics

2 answers:

zhenek [66]3 years ago

8 0

Answer:

$y-3= -\frac{1}{5}(x-5)$

Step-by-step explanation:

Fill in what you know: ( $y=-\frac{1}{5}x+b$ )
Solve for b with test point (5, 3): ( $3=-\frac{1}{5}*5+b$ )

$b=4$

Convert to point-slope form: $y-3= -\frac{1}{5}(x-5)$

iren [92.7K]3 years ago

3 0

Answer:

y-3= -1/5(x-5)

Step-by-step explanation:

point slope form is --> y-y,=m(x-x,)

commas represent 1's.

-1/5= m

3=y,

5=x,

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Answer:

Proof in explanation.

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I'm going to attempt this by squeeze theorem.

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By squeeze theorem, if $-x^4 \le x^4 \cos(\frac{2}{x}) \le x^4$

and $\lim_{x \rightarrow 0}-x^4=\lim_{x \rightarrow 0}x^4=L$ , then we can also conclude that $\im_{x \rightarrow} x^4\cos(\frac{2}{x})=L$ .

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