The answer is 7. If you follow the order of PEMDAS this is an easy question.
Answer:
see below
Step-by-step explanation:
The formula for the sum of an infinite geometric series with first term a1 and common ratio r (where |r| < 1) is ...
sum = a1/(1 -r)
Applying this to the given series, we get ...
a. sum = 5/(1 -3/4) = 5/(1/4) = 20
b. sum = d/(1 -1/t) = d/((t-1)/t) = dt/(t-1)
_____
The derivation of the above formula is in most texts on sequences and series. In general, you write an expression for the difference of the sum (S) and the product r·S. You find all terms of the series cancel except the first and last, and the last goes to zero in the limit, because r^∞ → 0 for |r| < 1. Hence you get ...
S -rS = a1
S = a1/(1 -r)
First, find the digit in the place you are rounding to. Look at the digit one place to the right. If the digit is less than 5, round down. If the digit is 5 or greater, round up.
For example: round 1.86 to the nearest tenth
Look at the tenth digit (8). The number to the right of it is 6. Since it’s above 5, round the 8 up to 9. So you would get 1.9.
If it was 1.84, since 4 is less than 5, you would not round the 8, and you would get 1.8
Answer:
x = - 
Step-by-step explanation:
Given
(x + 5 
) = 
Multiply both sides by 8 to clear the fractions
6(x + 5 ) = 5 ← distribute parenthesis on left side
6x + 33 = 5 ( subtract 33 from both sides )
6x = - 28 ( divide both sides by 6 )
x = 
= -
