Slope-intercept form. need help!

Find the standard deviation of the data, 12, 19, 9.

jek_recluse [69]

Answer:

4.19

Step-by-step explanation:

Find the mean:

$\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}$

Find the standard deviation:

$\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19$

4 0

1 year ago

mb- The graph shows the relationship between time and the number of soda bottles a machine can make. Use the points (2,100) and

Evgesh-ka [11]

Answer:

1200

Step-by-step explanation:

We can gather from what's given that y=20xy represents the total number of bottles produced in the given time in seconds, which is x. When x=1, y=20, This means that each second the machine can make 20 soda bottles. Each minute is 60 seconds, so when x=60, y=20*60 =1200 soda bottles.

5 0

2 years ago

DEVISION DE UN MONOMIO POR UN MONOMIO

frozen [14]

איך טאָן ניט פֿאַרשטיין מיין שטאָף

3 0

1 year ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

1 year ago

which pair of these points defines a line with a slope 2/3? A. (2, 6) and (3, 0) B. (6, 2) and 3, 0) C. (6, 2) and (0, 0) D. (2,

ipn [44]

Answer:

B. (6,2) and (3,0)

Step-by-step explanation:

To find the slope the equation is $\frac{y_{2-y_{1} } }{x_{2} -x_{1} }$ so for (6,2) and (3,0) the equation would look like this $\frac{0-2}{3-6}$ which simplies down to $\frac{-2}{-3}$ and a negative divided by a negative is a positive so you're slope is $\frac{2}{3}$ and it matches the question.

3 0

2 years ago

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