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ki77a [65]
3 years ago
14

Need help on this please

Mathematics
1 answer:
Delvig [45]3 years ago
6 0
The answer would be skewed right
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C. density = mass / volume

Step-by-step explanation:

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Henry made 200 tarts. He sold 5 of them and gave 4 of the remainder to
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191

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200 minus 4 and five equal 191

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How do I solve the equation.×-8=4 can you help me with step by steps on this please
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A boat travels 33 miles downstream in 4 hours. The return trip takes the boat 7 hours. Find the speed of the boat in still water
Paha777 [63]

<u>Answer:</u>

Speed of the boat in still water = 6.125 miles/hour

<u>Step-by-step explanation:</u>

We are given that a boat travels 33 miles downstream in 4 hours and the return trip takes the boat 7 hours.

We are to find the speed of the boat in the still water.

Assuming S_b to be the speed of the boat in still water and S_w to be the speed of the water.

The speeds of the boat add up when the boat and water travel in the same direction.

Speed = \frac{distance}{time}

S_b+S_w=\frac{d}{t_1}=\frac{33 miles}{4 hours}

And the speed of the water is subtracted from the speed of the boat when the boat is moving upstream.

S_b-S_w=\frac{d}{t_2}=\frac{33 miles}{7 hours}

Adding the two equations to get:

   S_b+S_w=\frac{d}{t_1}

+  S_b-S_w=\frac{d}{t_2}

___________________________

2S_b=\frac{d}{t_1} +\frac{d}{t_2}

Solving this equation for S_b and substituting the given values for d,t_1, t_2:

S_b=\frac{(t_1+t_2)d}{2t_1t_2}

S_b=\frac{(4 hour + 7hour)33 mi}{2(4hour)(7hour)}

S_b=\frac{(11 hour)(33mi)}{56hour^2}

S_b=6.125 mi/hr

Therefore, the speed of the boat in still water is 6.125 miles/hour.

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How will I be able to use subtraction to find lengths of segments,for instance WX an XY
ziro4ka [17]
You subtract the greater one from the smaller one and you get the difference.
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3 years ago
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