Simplify: –3(y + 2)2 – 5 + 6y What is the simplified product in standard form?

Mathematics

2 answers:

ch4aika [34]3 years ago

5 0

<h3>Solution:</h3>

$- 3{(y + 2)}^{2} - 5 + 6y \\ - 3(y + 2)(y + 2) - 5 + 6y \\ ( - 3y - 6)(y + 2) - 5 + 6y \\ - 3 {y}^{2} - 6y - 6y - 12 - 5 + 6y \\ - 3 {y}^{2} - 12y - 12 - 5 + 6y \\ - 3 {y}^{2} - 12y + 6y - 12 - 5 \\ - 3 {y}^{2} - 6y - 17$

<h3>Answer</h3>

$-3y^{2}-6y-17$

Helga [31]3 years ago

4 0

Answer:

-17

Step-by-step explanation:

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3 divided by 6 it hard

stira [4]

Answer:

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Step-by-step explanation:

3 / 6 = 1/2 = 0.5

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3 years ago

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What is the radius of a sphere with a volume of 1/6 pie

Yakvenalex [24]

Answer:

$\large\boxed{the\ radius\ R=\dfrac{1}{2}}$

Step-by-step explanation:

The formula of a volume of a sphere:

$V=\dfrac{4}{3}\pi R^3$

We have

$V=\dfrac{1}{6}\pi$

Substitute:

$\dfrac{4}{3}\pi R^3=\dfrac{1}{6}\pi$ <em>divide both sides by π</em>

$\dfrac{4}{3}R^3=\dfrac{1}{6}$ <em>multiply both sides by 3</em>

$3\!\!\!\!\diagup^1\cdot\dfrac{4}{3\!\!\!\!\diagup_1}R^3=3\!\!\!\!\diagup^1\cdot\dfrac{1}{6\!\!\!\!\diagup_2}$

$4R^3=\dfrac{1}{2}$ <em>divide both sides by 4</em>

$R^3=\dfrac{1}{2}:4\\\\R^3=\dfrac{1}{2}\cdot\dfrac{1}{4}\\\\R^3=\dfrac{1}{8}\to R=\sqrt[3]{\dfrac{1}{8}}\\\\R=\dfrac{\sqrt1}{\sqrt8}\\\\R=\dfrac{1}{2}$