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3 years ago

What is the value of b^2 - 4ac for the following equation?

Mathematics

1 answer:

WINSTONCH [101]3 years ago

5 0

(7)^2-4(5)(-6)=

49+120=169 is the answer

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What is the product of 5the square root of 3. • 4the square root of 15.? Simplify if possible. 60the square root of 5. 20the squ

svp [43]

Correct Answer: $60 \sqrt{5}$

We are to find:

$5 \sqrt{3} *4 \sqrt{15}$

Multiplying and simplifying the radicals, we get:

$20 \sqrt{45} \\ \\ 
=20 \sqrt{9*5} \\ \\ 
=20*3 \sqrt{5} \\ \\ 
=60 \sqrt{5}$

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Whats a common facter of 32 and 36

KengaRu [80]

Common Factors of 32 and 36
factors of 32 = 1, 2, 4, 8, 16 and 32
factors of 36 = 1, 2, 3, 4, 6, 9, 18, 36
<span>So the common </span>factors of 32 and 36 are 1, 2 and 4.
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Simplify the surd 3√ 20 +√ 45

melisa1 [442]

Answer:

9 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the radicals

$\sqrt{20}$

= $\sqrt{4(5)}$

= $\sqrt{4}$ × $\sqrt{5}$

= 2 $\sqrt{5}$

$\sqrt{45}$

= $\sqrt{9(5)}$

= $\sqrt{9}$ × $\sqrt{5}$

= 3 $\sqrt{5}$

Then

3 $\sqrt{20}$ + $\sqrt{45}$

= 3(2 $\sqrt{5}$ ) + 3 $\sqrt{5}$

= 6 $\sqrt{5}$ + 3 $\sqrt{5}$

= 9 $\sqrt{5}$

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