Hi,
I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:
#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
short T;
cin >> T;
cin.ignore();
string str[100];
for(int i=0; i<T; i++)
{
getline(cin, str[i]);
}
for (int i = 0; i < T; i++)
{
stringstream ss(str[i]);
string tmp;
vector<string> v;
while (ss >> tmp)
{
// Let's capitalize it before storing in the vector
if (!tmp.empty())
{
transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
tmp[0] = toupper(tmp[0]);
}
v.push_back(tmp);
}
if (v.size() == 1)
{
cout << v[0] << endl;
}
else if (v.size() == 2)
{
cout << v[0][0] << ". " << v[1] << endl;
}
else
{
cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
}
}
return 0;
}
Answer:
IT security is a set of cyber security strategies that prevents unauthorized access to organizational assets such as computers, networks, and data.
Answer:
Aye dog I don't know nothing about code, yes its true, but I hope that you get an answer for you!
Explanation:
Facts...
Answer:
Net force = 20 N
Explanation:
Given that,
Force acting on the left = 10 N
Force acting on the right = 30 N
Let right side is positive and left side is negative. Let the net force acting on the box is F. So,
F = -10+30
F = 20 N
So, the net force on the box is 20 N and it is in right side.
