Would my phone still work if I snapped it in half?

There are no breakpoints in the "Access Customer Account" subpage however there is an error. What will happen if you choose to s

blsea [12.9K]

Answer:

Move to the breakpoint at "Get Customer Details" stage.

Explanation:

This question is incomplete, we need a diagram and four options to resolve this questions, I attached the diagram and the options.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the breakpoint at "Get Customer Details" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Recover1" stage.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the stage containing the error on the "Access Customer Account" page.

- The process will work all stages in the "Access Customer Account" page until the error is thrown and then focus would move to the "Exception1" stage.

In this case, we are going to run an extra from subpage testing in <u>Process studio</u>. Process studio is a tool where we can test these processes.

The process always it's going to work all stages in the "Access Customer Account" we're going to receive an interruption when the error is activated, moving the focus to the Get Customer Details stage.

There is an error in the stage Access Customer Account, if we run the processes with the Go button, the focus should move into the Recover1 stage, and should show the error.

But in this particular example, we must use the STEP OUT BUTTON, What means this?

The process it's going be executed, but won't show any error or message, because we have used the STEP OUT BUTTON.

If we use the STEP OUT BUTTON, the process should end but in this case, we have a breakpoint in Get Customer Details stage, for that the focus and the process will end in Get Customer Details stage and not at the end or at the Recover1 stage.

8 0

3 years ago

Write a routine to interchange the mth and nth elements of a singly-linked list. You may assume that the ranks m and n are passe

IRINA_888 [86]

Answer:

//The routine to swap m th and nth ranked elements

void swapmAndn(int m, int n)

{

//Set the linked list head node

Linked_Node **node_head

//To find the m ranked node

//set previous node

Linked_Node *node_prev = NULL;

//set node to store m ranked node as head node

Linked_Node *node_current_m = *node_head;

//set the rank as rm=1

rm =1

//traverse to find the m ranked node

while (node_current_m && rm<m)

{

node_prev = node_current_m;

node_current_m = node_current_m->next;

rm++;

}

//To find the n ranked node

//set previous node

Linked_Node *node_prev_n = NULL;

//set node to store n ranked node as head node

Linked_Node *node_current_n = *node_head;

//set the rank as rn=1

rn =1

//traverse to find the n ranked node

while (node_current_n && rn<n)

{

node_prev_n= node_current_n;

node_current_n = node_current_n->next;

rn++;

}

//if m is not first ranked node

if (node_prev != NULL)

//set node_current_n as previous node

node_prev->next = node_current_n;

//otherwise Set the node_current_n

else

*node_head = node_current_n;

// If n is not first ranked node

if (node_prev_n!= NULL)

node_prev_n->next = node_current_m;

else

*node_head = node_current_m;

//now swap the next pointers also

//to make the swap process complete

Linked_Node *temp = node_current_n->next;

node_current_n->next = node_current_m->next;

node_current_m->next = temp;

}

Explanation:

3 0

3 years ago

"Create a Matlab Scrapt that will take the a Matrix A and Matrix B (of AX=B), then calculate the Determinant of Matrix A, Invers

prohojiy [21]

Answer:

see explaination

Explanation:

function [] =

inverse(A,B)

da = det(A);

disp("The det of A is");

disp(da);

inva = inv(A);

disp("The inverse of A is");

disp(inva);

x = inva*B;

disp("The value of X is");

disp(x);

rk = rank(A);

disp("The rank of X is");

disp(rk);

Di = eig(A);

disp("The eigen values of A is");

disp(Di);

[V,Di] = eig(A);

disp("The eigen vectors of A are (Each column represents one column vector)");

disp(V);

end

A = [1,2;4,5];

B = [1,2;4,5];

inverse(A,B);

%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];

%disp(ab);

4 0

3 years ago

It is important to create an IT security program structure that aligns with program and organizational goals and describes the o

AleksandrR [38]

Answer:

Management and coordination of security-related resources

Explanation:

It is essential to make sure that an information security program is highly secured and non-authorized personnel cannot get access to the program. The security of the program is also important to ensure that valuable information and data of clients are safe. This is one of the most vital in security management.

8 0

4 years ago

Write a loop that sets newScores to oldScores shifted once left, with element 0 copied to the end. Ex: If oldScores = {10, 20, 3

Anarel [89]

Answer:

The code to this question can be given as:

Code:

int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.

newScores = oldScores; //holds value.

for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.

{

newScores.at(i) = newScores.at(i+1); //holds value in newScores.

}

newScores.at(lastVector) = oldScores.at(0); //moving first element in last.

Explanation:

In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
Then we use another for loop for print newScores array elements.

4 0

3 years ago