Answer:
Earths moon:
Scientific: 7.35x10^22
Standard:73500000000000000000000
for the rest im only going to give you the scientific method
Mercury: 3.205x10^23
Venus 4.867x10^24
Jupiter 1.898x10^27
Saturn 5.683x10^26
Uranus 8.681x10^25
Neptune 1.024x10^26
Phobos 10.6x10^15
Ariel 1.27x10^21
Titan 1.3452x10^23
I hope this helps
Answer:
8
Step-by-step explanation:
the ratio or fraction for this problem would be 1 (gold coin) : 25 (points)
If we want to find out how many gold coins he needs to get 200 points we need to divide 200 by 25.
200/25 : 8
if we want to check our answer do this
1:25
1 x 8 is 8
25 x 8 is 200
Soo... Collin needs to find 8 coins to win 200 points.
hope i helped
Answer:
The answer would the third option "Yes, because there is enough water in the cooler for about 81 cups total."
Step-by-step explanation:
2 3/4a=19 1/4
÷2 3/4 ÷2 3/4
a=1/7
Step-by-step explanation:
(a)
Using the definition given from the problem
![f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\](https://tex.z-dn.net/?f=f%28A%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B0%2C2%5D%5C%7D%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%20%3D%20%5C%7Bx%5E2%20%20%5C%2C%20%3A%20%5C%2C%20x%20%5Cin%20%5B1%2C4%5D%5C%7D%20%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccap%20f%28B%29%20%3D%20%5B1%2C4%5D%20%20%3D%20f%28A%20%5Ccap%20B%29%5C%5C)
Therefore it is true for intersection. Now for union, we have that
![A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20%5B0%2C4%5D%5C%5Cf%28A%5Ccup%20B%20%29%20%3D%20%5B0%2C16%5D%5C%5Cf%28A%29%20%3D%20%5B0%2C4%5D%5C%5Cf%28B%29%3D%20%5B1%2C16%5D%5C%5Cf%28A%29%20%5Ccup%20f%28B%29%20%3D%20%5B0%2C16%5D)
Therefore, for this case, it would be true that 
.
(b)
1 is not a set.
(c)
To begin with
Therefore
Now, given an element of 
it will belong to both sets, therefore it also belongs to 
, and you would have that
, therefore 
.
(d)
To begin with 
, therefore
