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Ierofanga [76]
3 years ago
14

Pls help with these questions

Mathematics
1 answer:
postnew [5]3 years ago
3 0

Find x-intercept and y-intercept then you can draw the graph.

For example, the first question.

y=-3x+2

To find the y-intercept, x = 0

So substitute x = 0 in the equation.

y=0+2\\y=2

[Note]: You don't need to find the y-intercept, because from, y=ax+b

a is slope and b is y-intercept, you know b then you know y-intercept. For example b = 2 then y-intercept is at 2.

To find the x-intercept, y = 0

-3x+2=0\\-3x=-2\\x=\frac{2}{3}

Therefore, y-intercept = 2 and x-intercept = 2/3

(Try do another problems, just do the same. When you want to find the y-intercept, just look at the value of b or substitute x = 0 and When you want to find the x-intercept, just substitute y = 0 then solve for x.)

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mash [69]

Answer:

(-6,9,-3)

Step-by-step explanation:

-3x -y +z=6

-3x-y+3z =0

x-3z =3

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-1 *(-3x-y+3z) =0*-1

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Add this to the first equation

-3x -y +z=6

3x +y -3z =0

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-2z/-2 = 6/-2

z = 6/-2

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Take the third equation to find x

x-3z=3

x-3(-3) = 3

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Now we need to find y

3x +y -3z =0

3(-6) +y -3(-3) =0

-18 +y +9=0

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Add 9 to each side

-9+9+y = 0+9

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(-6,9,-3)

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Answer:

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Answer:

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GuDViN [60]

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