Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
C
Step-by-step explanation:
The data is skewed, and the lowest number of crackers in a package was 7
Answer:
Hi! The answer to your question is C. 52
Step-by-step explanation:
☆*: .。..。.:*☆☆*: .。..。.:*☆☆*: .。..。.:*☆
☆Brainliest is greatly appreciated!☆
Hope this helps!
- Brooklynn Deka
Answer:
C. The temperature was 32 degrees higher when t = 7 than when t = 3
Step-by-step explanation:
cause i big brain
Use distance formula
=√(3-3)^2 +(-4-4)^2
=√64
=8