1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Irina-Kira [14]
3 years ago
9

Evaluating expressions k3+j

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0
The answer is 3k+j since 3 cannot be multiplied after k.
You might be interested in
X+12=31 solve for x i’m in a breakout room i have limited time to finish this
Nitella [24]

Answer: x=19

Step-by-step explanation:

x=31-12

x=19

4 0
2 years ago
Find the Highest Common Factor (HCF) of 196 and 12
Norma-Jean [14]

Answer:

The greatest common factor is 4

Step-by-step explanation:

1.Find the prime factorization of 12

         a) 12 = <u>2</u> × <u>2</u> × 3

2.Find the prime factorization of 196

         a) 196 =<em> </em><u>2</u> ×<u> 2</u> × 7 × 7

To find the GCF, multiply all the prime factors common to both numbers:

          a)GCF=2x2

Therefore, GCF = 2 × 2

GCF = 4

7 0
3 years ago
Read 2 more answers
What is the exact distance from (−4, −2) to (4, 6)?
PIT_PIT [208]
Hopefully this is right :)

8 0
3 years ago
The mean number of hours per day spent on the phone, according to a national survey, is four hours, with a standard deviation of
Reika [66]

Answer:

The new mean is 5.

The new standard deviation is also 2.

Step-by-step explanation:

Let the sample space of hours be as follows, S = {x₁, x₂, x₃...xₙ}

The mean of this sample is 4. That is,\bar x=\frac{x_{1}+x_{2}+x_{3}+...+x_{n}}{n}=4

The standard deviation of this sample is 2. That is, s=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}=2.

Now it is stated that each of the sample values was increased by 1 hour.

The new sample is: S = {x₁ + 1, x₂ + 1, x₃ + 1...xₙ + 1}

Compute the mean of this sample as follows:

\bar x_{N}=\frac{x_{1}+1+x_{2}+1+x_{3}+1+...+x_{n}+1}{n}\\=\frac{(x_{1}+x_{2}+x_{3}+...+x_{n})}{n}+\frac{(1+1+1+...n\ times)}{n}\\=\bar x+1\\=4+1\\=5

The new mean is 5.

Compute the standard deviation of this sample as follows:

s_{N}=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=\frac{1}{n-1}\sum ((x_{i}+1)-(\bar x+1))^{2}\\=\frac{1}{n-1}\sum (x_{i}+1-\bar x-1)^{2}\\=\frac{1}{n-1}\sum (x_{i}-\bar x)^{2}\\=s

The new standard deviation is also 2.

5 0
3 years ago
The flow of financial data through the accounting information system does NOT include a. receiving payment for all accounts rece
Leokris [45]

Answer:

a. receiving payment for all accounts receivable.

Step-by-step explanation:

The flow of financial data through the accounting information system does NOT include - receiving payment for all accounts receivable.

The flow of data through the accounting information system includes analyzing transactions, journalizing and posting transactions and preparing a trial balance.

7 0
3 years ago
Other questions:
  • What are the slope and the y-intercept of the linear function that is represented by the table?
    7·2 answers
  • Explain what happens to the decimal point in a whole number when you divide it by a power of 10 use this problem with your expla
    8·1 answer
  • MR Husted has a wooden parallelogram which has a height of 4 centimeters and a base of 11 centimeters. ms Henningsen also has a
    15·1 answer
  • Solve the following equations for y.<br> 9. 2y + 3= 2x
    15·1 answer
  • Is the following relation a function? Graph of x equals y squared, which results in a horizontal parabola centered on the x axis
    13·2 answers
  • Un padre para estimular a su hijo para estudiar matemáticas le dice: por cada ejercicio que resuelvas bien te daré 7 € y por cad
    8·1 answer
  • The diagram is not drawn to scale
    15·1 answer
  • Solve: |4x+3|=|2x+1|
    15·2 answers
  • Find the area of the following shape. Please show your work.
    13·1 answer
  • −4x−y=24minus, 4, x, minus, y, equals, 24Complete the missing value in the solution to the equation.
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!