The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.
<h3>What is speed?</h3>
Speed can be calculated as the ratio of distance traveled to the time taken.
The speed that a tsunami can travel is modeled by the equation
s = 356√d, where s is the speed in kilometers per hour and d is the average depth of the water in kilometers.
S = 356√d
200 = 356√d
√d = 200/356
= 0.5618
d = 0.5618^2
= 0.316 km
d = 0.32 km.
Thus, The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.
Learn more about speed;
brainly.com/question/4723349
Answer:
His score decreased by 9 percent this time.
Step-by-step explanation:
From his first history exam he had a score of 90 percent. The difference between his first score and present score is given by
90 - 81 = 9
Answer:
r^2 * 1/s^4 * t^5
Step-by-step explanation:
r^2 * 1/s^4 * t^5
s^-4 = 1/s^4
20,000,000+400,000+80,000+4,000+100+60+3
Answer:
177 ft below sea level.
Step-by-step explanation:
Initial altitude of the hot air balloon = 282 below sea level
Rate of rise of balloon = 10 ft / second
Time = 12 seconds
Total rise in 12 seconds = Rate of rise of balloon
Time
= 120 ft
Now, we will have to subtract to find the new altitude.
New altitude = 282 - 120 = 162 ft
Now, it is given that balloon Captain lowers the balloon 15 ft.
To find the final altitude, we will have to add it to the previous altitude.
Therefore, the final altitude = 162 + 15 = <em>177 ft below sea level </em>