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elena-s [515]
3 years ago
15

Can someone help me understand how to name polynomials??

Mathematics
1 answer:
Serhud [2]3 years ago
8 0

A polynomial can have  

constants

variables

exponents

that can be combined using addition, subtraction, multiplication and division ...

... except ...

... not division by a variable

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HELP HELP HELP PLS SOMEBODY PLS
Elodia [21]

Answer:

A) Both estimates are slightly larger, so it is reasonable.

Step-by-step explanation:

Since 1/2 = 5/10

And 1/5 = 8/40

<u>Both estimates are larger</u>

7 0
3 years ago
What is the exact area of a circle with a diameter of 10 cm? a. 5πcm^2 b. 10πm^2 c. 25πcm^2 d. 100πcm^2
dalvyx [7]

Answer:

C

Step-by-step explanation:

a=\pir^2

To find the radius, divide the diameter by 2

r=d/2

r=10/2

r=5

a=\pir^2

a=\pi5^2

a=25\pi

So, choice C is correct

Hope this helps! :)

4 0
3 years ago
What is 1.48888 repeating as a fraction
Alik [6]
1/4 I think because you would limit the eights
6 0
3 years ago
Read 2 more answers
The animal department wants to estimate baboon population. So they paint 50 baboons with a mark. These baboons were then release
Svet_ta [14]

Answer:

  600 baboons

Step-by-step explanation:

Half the number of marked baboons showed up in the sample, so we expect the sample size to be about half of the total population. 300 is half of 600.

___

Many assumptions are involved in such an experiment and analysis. Not the least of which are the assumptions that the marked baboons end up evenly distributed through the population, and that the sample is a fair sample of the entire population.

3 0
3 years ago
What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (
aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

in this problem we have

the point (5,12) is on the line of direct variation

so

Find the constant of proportionality k

y/x=k-------> substitute ------> k=12/5

the equation is

y=\frac{12}{5}x

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point (0,0)

x=0\ y=0

Substitute the value of x and y in the direct variation equation

0=\frac{12}{5}*0

0=0 -------> is true

therefore

the point (0,0) is on the line of direct variation

<u>case B)</u> point (2.5,6)

x=2.5\ y=6

Substitute the value of x and y in the direct variation equation

6=\frac{12}{5}*2.5

6=6 -------> is true

therefore

the point (2.5,6) is on the line of direct variation

<u>case C)</u> point (3,10)

x=3\ y=10

Substitute the value of x and y in the direct variation equation

10=\frac{12}{5}*3

10=7.2 -------> is not  true

therefore

the point (3,10) is not on the line of direct variation

<u>case D)</u> point (7.5,18)

x=7.5\ y=18

Substitute the value of x and y in the direct variation equation

18=\frac{12}{5}*7.5

18=18 -------> is true

therefore

the point (7.5,18) is on the line of direct variation

<u>case E)</u> point (12.5,24)

x=12.5\ y=24

Substitute the value of x and y in the direct variation equation

24=\frac{12}{5}*12.5

18=30 -------> is not true

therefore

the point  (12.5,24) is not on the line of direct variation

<u>case F)</u> point (15,36)

x=15\ y=36

Substitute the value of x and y in the direct variation equation

36=\frac{12}{5}*15

36=36 -------> is true

therefore

the point (15,36) is on the line of direct variation

therefore

<u>the answer is</u>

(0,0)

(2.5,6)

(7.5,18)

(15,36)


5 0
3 years ago
Read 2 more answers
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