In this formula :

y tells us how far up the line goes
x tells us how far along
m is the Slope or Gradient i.e. how steep the line is
b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line 3x+2y-62 = 0 and calculate its properties

Notice that when x = 0 the value of y is 31/1 so this line "cuts" the y axis at y=31.00000

y-intercept = 62/2 = 31

When y = 0 the value of x is 62/3 Our line therefore "cuts" the x axis at x=20.66667

x-intercept = 62/3 = 20.66667

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is 31.000 and for x=2.000, the value of y is 28.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 28.000 - 31.000 = -3.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = -3.000/2.000 = -1.500


1.Slope = -3.000/2.000 = -1.500

2.x-intercept = 62/3 = 20.66667

3.y-intercept = 62/2 = 31

I got sources from a few websites so excuse if something is weird/wrong.

4 0

3 years ago

For the month of January in a certain city, 42% of the days are cloudy. Also in the month of January in the same city, 41% o

zalisa [80]

Answer: 0.9762

Step-by-step explanation:

Let A be the event that days are cloudy and B be the event that days are rainy for January month .

Given : The probability that the days are cloudy = $P(A)=0.42$

The probability that the days are cloudy and rainy = $P(A\cap B)=0.41$

Now, the conditional probability that a randomly selected day in January will be rainy if it is cloudy is given by :-

$P(B|A)=\dfrac{P(B\cap A)}{P(A)}\\\\\Rightarrow\ P(B|A)=\dfrac{0.41}{0.42}=0.97619047619\approx0.9762$

Hence, the probability that a randomly selected day in January will be rainy if it is cloudy = 0.9762

7 0

3 years ago