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zvonat [6]
4 years ago
12

a group of 5 friends is sharing 2 pounds of trail mix. write a division problem and a fraction to represent this situation

Mathematics
1 answer:
Stolb23 [73]4 years ago
6 0
2➗5 for a division problem and for a fraction it is 2/5
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How do i solve 0.074 x n equals 74
Serhud [2]
0.074n = 74
multiply both sides by 1000 to make the process simpler
74n = 74000
divide both sides by 74
n = 1000
3 0
3 years ago
Read 2 more answers
I need the answer please.
Anestetic [448]

2 1/4 = 9/4

(9/4)(8/5) = (9/1)(2/5) = 18/5 = 3 3/5 cups

5 0
4 years ago
Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
KiRa [710]

Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

6 0
3 years ago
Elle’s family decided to save money for her to attend college after she graduates from high school. On the day she was born, Ell
svetoff [14.1K]

Answer:

A person standing on a moving walkway travels 60 feet in 20 seconds. What equation represents this relationship? How many feet will person travel 10 seconds?

Step-by-step explanation:

HELP ME

5 0
3 years ago
Question set 2: Many species of terrestrial tree frogs that hibernate at or near the ground surface can survive prolonged exposu
joja [24]

Answer:

0.86

Step-by-step explanation:

The z-score we need to make the comparison is given by

\bf z=\frac{-2.05-(-2)}{\sigma/\sqrt{n}}

where

\bf \sigma= the standard deviation established in the study

n = the sample size

\bf z=\frac{-2.05-(-2)}{0.3/\sqrt{42}}=-1.0801

and for the Normal distribution N(0,1) we want to find  

<em>P(X > -1.0801) </em>

By using a spreadsheet or the table attached, we find that

P(X > -1.0801) = 0.86

(See picture attached)

7 0
3 years ago
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