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Montano1993 [528]
3 years ago
10

The first stage of a rocket burns 28 seconds longer than the second stage. If the total burning time for both stages is 152 seco

nds then how long does each stage burn? Solve.
Mathematics
1 answer:
maria [59]3 years ago
4 0
The 1st stage: x,  the 2nd stage:  y.
x + y = 152
x = y + 28
y + 28 + y = 152
2 y = 152 - 28
2 y = 124
y = 124 : 2 = 62
x = 62 + 28 = 90
Answer: the first stage burns 90 seconds and the second burns 62 seconds.
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4 0
3 years ago
Kerrie uses the work shown below to determine 35% of 280.
lys-0071 [83]

For this case we must find 35% of 280.

Kerrie gets 10% and then 25%. So:

10% of 280:

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x -----------------> 10%

Where "x" represents the amount given by 10% of 280.

x = \frac {10 * 280} {100}\\x = 28

Thus, 10% of 280 is 28.

Now, we find 25% of 280:

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Where "x" represents the amount given by 25% of 280.

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Thus, 25% of 280 is 70.

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Answer:

Option A

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3 years ago
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