Answer:
1920 square inches
Step-by-step explanation:
For a rectangular prism, the lateral area can be found by ...
LA = Pl
where P is the perimeter, and l is the length.
For a square pyramid, the lateral area can be found by ...
LA = (1/2)Ph
where P is the perimeter of the base, and h is the slant height of the triangular faces.
For a figure with a square cross section of perimeter P "capped" by square pyramids on either end, the total surface area is the sum of the lateral areas of the three components:
SA = (Pl) + (1/2)Ph + (1/2)Ph
SA = P(l+h) = (4×15 in)(14 +18 in) = (60)(32) in²
SA = 1920 in²
The surface area of the solid seems to be 1920 square inches.
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<em>Caveat</em>
If the figure is something other than what we have tried to describe, your mileage may vary. A diagram would be helpful.
Answer:
i added an attachment of the graph :)
Step-by-step explanation:
Answer:
1st one: -3,-4 away
2nd one: Lets just say I got kinda confused on that one so sorry for any inconvenience on my behalf from this question.
Step-by-step explanation:
I will call (-3,-4) Point A and I'll call (0,0) Point B. Point A is at (-3,-4) and Point B is obviously at the origin. That makes it easy, because you just subtract Point A by Point B to find how far away they are.
Answer:
The correct options are:
Option B)
is never zero.
Option F) When x=0, y≠0
Step-by-step explanation:
Consider the provided function.

When we substitute x=0 in above function we get:


When we substitute x=-1 in above function we get:


When we substitute x=1 in above function we get:


The above function is exponential function which does not pass through the origin and the range of the function is a positive number.
The graph of the function is shown in figure 1.
Now consider the provided options.
Option A)
is always greater than or equal to 1.
The option is incorrect as the value of the function is less than 1 for negative value of x.
Option B)
is never zero
The option is correct.
Option C) When y=0, x=0
The option is incorrect.
Option D) When x=0, y=4
When x=0 the value of y is 1.
Thus, the option is incorrect.
Option E)
is zero when x=0
When x=0 the value of
is 1.
Thus, the option is incorrect.
Option F) When x=0, y≠0
The option is correct as 0≠1.