51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6
52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0 and x=-3/2=-1.5
53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5
54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
Step-by-step explanation:
or, 6m=5/13
or, m=5/13 ×6m
m=30/13
Answer:
7.8
Step-by-step explanation:
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.