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erma4kov [3.2K]
3 years ago
10

a water drum in the shape of a rectangular prism measures 5m by 4 m by 2 m. It is completely full of water. The water is siphone

d into a cylindrical tank of diameter 3 m. How far up the side of the tank will the water reach?
Mathematics
1 answer:
valina [46]3 years ago
7 0
First of all, the definition of siphoned according to the online dictionary is: 
<span>"a tube </span>used to<span> convey liquid upwards from a reservoir </span>and then <span>down to a lower level of its </span>own <span>accord. Once the liquid </span>has been <span>forced into the tube, </span>typically<span> by suction or immersion, </span>flow continues unaided<span>.'

LOL, the definition doesn't make any difference. Let's actually solve the questions now. 

First, find the volume of the water drum which is 5x4x2= 40m^2. (remeber it is "completely full of water")
</span>
Second, divided it by (1.5)^2 x(pi). Essentially you are dividing the volume of water by the surface area of one side of a cylinder. (note: I square 1.5 since you use the radius not the diameter for the calculation)

Please rate it high and send a personal message if you want me to answer more questions for free. 


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Answer: Surface area is equal to 200cm^{2}

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Step-by-step explanation:

First, let's do surface area.

The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base

The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.

The lateral height is given as 5 cm.

The area of the base is 10(10) = 100.

We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200cm^{2}.

Now for volume.

The volume of a pyramid is equal to 1/3(area of the base)(height).

We already have the area of the base, which is 100.

The height is given as 10 cm.

Plugging those numbers into the equation, we get 1/3(100)(10), which is 1000/3 or about 333.33cm^{3}.

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