9514 1404 393
Answer:
(x, y, z) = (1/3, 2/3, 1)
Step-by-step explanation:
We can use the first equation to write an expression for x that can be substituted into the other equations.
x = 1 -y
2(1 -y) -y +z = 1 ⇒ -3y +z = -1
(1 -y) +2y +z = 8/3 ⇒ y +z = 5/3
Subtracting the first of these equations from the second gives ...
(y +z) -(-3y +z) = (5/3) -(-1)
4y = 8/3
y = 2/3
z = 5/3 -y = 1
x = 1 -y = 1/3
The solution is (x, y, z) = (1/3, 2/3, 1).
First you want to subtract 36
so it looks like this ![\sqrt[4] {(4x+164)^3}=64](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%20%7B%284x%2B164%29%5E3%7D%3D64)
Then you want to cancel out the square root 4 by raising that to the 4th power (you must do this to both sides)
which is equal to 
Then you take the cube root to both sides [tex]\sqrt[3]{(4x+164)^3}=\sqrt[3]{16777216}[tex]
Then you end up with the equation 4x+164=256
Then subtract 164 to both sides
4x=92
then divide 92 by 4
Then you get x=23
Answer:
14:15
Step-by-step explanation: By reading the sentence carefully you should be able to get the first number and the second number. The sentence should tell you how to set it up.
Answer:
You go to whoever's question you wanna answer and it should say "add answer" and just type out your answer and solve it
Answer:
2x+15y=
Step-by-step explanation:
something like that
