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Nikitich [7]
3 years ago
13

Which are monomials?

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

Step-by-step explanation:

Monomials have only one term each.

Thus:

-7 is a monomial

a   is a monomial

x + y   is NOT a monomial ; it has two terms and is thus a binomial

1/x    is a monomial

24r^2st^3    is a monomial

ab/5    is a monomial

bx

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(a+b)²=?ahihihihihihihihihihihihi
aleksandr82 [10.1K]

Answer:

(a+b)²=a²+2ab+b²

Step-by-step explanation:

Hope this helps!!!

7 0
3 years ago
Read 2 more answers
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
In the circle below, AD is a diameter and AB is tangent at A. suppose mADC=228. Find the measures of mCAB and mCAD. Type your nu
Tju [1.3M]

Answer:

m∠CAB = 66°

m∠CAD = 24°

Step-by-step explanation:

<em>m∠CAB</em>

The given parameters are;

The measure of arc m\widehat{ADC} = 228°

The diameter of the given circle = \overline{AD}

The tangent to the circle = \underset{AB}{\leftrightarrow}

The measure of m∠CAB and m∠CAD = Required

By the tangent and chord circle theorem, we have;

m∠CAB = (1/2) × m\widehat{AC}

However, we have;

m\widehat{AC} + m\widehat{ADC} = 360° the sum of angles at the center of a circle is 360°

∴ m\widehat{AC} = 360° - m\widehat{ADC}

Which gives;

m\widehat{AC} = 360° - 228° = 132°

m\widehat{AC} = 132°

Therefore;

m∠CAB = (1/2) × 132° = 66°

m∠CAB = 66°

<em>m∠CAD</em>

Given that  \overline{AD} is the diameter of the given circle, we have

The tangent, \underset{AB}{\leftrightarrow}, is perpendicular to the radius of the circle, and therefore \underset{AB}{\leftrightarrow} is also perpendicular to the diameter of the circle

∴ m∠DAB = 90° which is the measure of the angle formed by two perpendicular lines

By angle addition property, we have;

m∠DAB = m∠CAB + m∠CAD

∴ m∠CAD =  m∠DAB - m∠CAB

By substitution, we have;

m∠CAD = 90° - 66° = 24°

m∠CAD = 24°

7 0
3 years ago
A bag contains 3 red marbles 4 white marbles and 5 blue marbles if one marble is drawn from the bag what is the probability that
snow_tiger [21]
5/12 because there are 5 blue marbles out of the 12 total marbles.
6 0
3 years ago
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