-7 degrees fahrenheit is warmer
<h2>
Answer with explanation:</h2>
Let
be the average starting salary ( in dollars).
As per given , we have

Since
is left-tailed , so our test is a left-tailed test.
WE assume that the starting salary follows normal distribution .
Since population standard deviation is unknown and sample size is small so we use t-test.
Test statistic :
, where n= sample size ,
= sample mean , s = sample standard deviation.
Here , n= 15 ,
, s= 225
Then, 
Degree of freedom = n-1=14
The critical t-value for significance level α = 0.01 and degree of freedom 14 is 2.62.
Decision : Since the absolute calculated t-value (2.07) is less than the critical t-value., so we cannot reject the null hypothesis.
Conclusion : We do not have sufficient evidence at 1 % level of significance to support the claim that the average starting salary of the graduates is significantly less that $42,000.
Answer:
b=5
Step-by-step explanation:
−4+bx=2x+3(x+1) (expand parenthesis first, i.e PEDMAS)
−4 + bx = 2x + 3x + 3
−4 + bx = 5x + 3 (move all x terms to one side and constants to another)
5x - bx = - 4 -3
5x - bx = - 7 (factor out x)
(5 - b)x = - 7
x = -7 / (5-b)
we can see that 5-b is in the denominator. Recall that for a fraction, the denominator cannot be zero otherwise the expression is undefined. (i.e no solutions)
hence the expression is undefined if,
(5-b) = 0
or b = 5