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3 years ago

Please help me with this long division problem. Thank you :)

Mathematics

2 answers:

trasher [3.6K]3 years ago

6 0

Answer:

Hey there! Your answer would be 0.529

Step-by-step explanation:

I used a calculator to get the best answer :) Have a good day!

velikii [3]3 years ago

5 0

I think the answer is 0.52

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~PLEASE HELP ASAP OFFERING 30 POINTS~

Ivenika [448]

The first one is B) september 10 but idk the second one

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3 years ago

Read 2 more answers

An aquarium measures 61 cm long, 30.5 cm wide, and 30.5 cm high.If the tank is only filled to 80% capacity with water, how much

LiRa [457]

Answer:

$V=45396.2\ cm^3$

Step-by-step explanation:

Given that,

The dimensions of an aquarium are 61 cm long, 30.5 cm wide, and 30.5 cm high.

The tank is filled to 80% capacity with water.

We need to find the water needed for this tank.

The volume of cuboid is given by :

$V=lbh$

As it is filled to 80% capacity, so,

$V=\dfrac{80}{100}\times lbh\\\\=0.8\times 61\times 30.5\times 30.5\\\\V=45396.2\ cm^3$

So, $45396.2\ cm^3$ of water is needed for this tank.

5 0

2 years ago

Wanda opened a savings account 20 years ago with a deposit of $3,150.37. The account has an interest rate of 4.1% compounded dai

Aleksandr [31]

$\bf ~~~~~~ \stackrel{daily}{\textit{Continuously Compounding Interest Earned Amount}}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3150.37\\
r=rate\to 4.1\%\to \frac{4.1}{100}\to &0.041\\
t=years\to &20
\end{cases}
\\\\\\
A=3150.37e^{0.041\cdot 20}\implies A=3150.37e^{0.82}\implies A\approx 7152.91457$

how much interest is there? well, A - 3150.37.

3 0

3 years ago

Identify as a direct variation, inverse variation or neither. is the cost of gasoline a direct or inverse variation with respect

r-ruslan [8.4K]

I would say direct because the more gallons of gasoline used, the bigger the cost.

8 0

3 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$

$X - 35000 = -1.88*7000$

$X = 21840$

The designed life should be of 21,840 vehicle miles.

3 0

3 years ago