Answer:The diagram shows a square ABCD.
D
N
bu
A
M
I
Mis the midpoint of AB.
Nis the midpoint of AD.
The area of the shaded triangle AMN is 18 cm
Work out the area of triangle MCN.
5b is the area of MCN
Step-by-step explanation:
Answer:
1. The two numbers are 4 and 8.
Step-by-step explanation:
1) variables: x and y
2) x + y = 12, y - x = 4
3) graph using desmos or another graphing calculator
4) the solution is x = 4, y = 8, or 4 and 8. This means that 4 and 8 can be added to equal 12, and the difference between them is 4.
Answer:
15 days
Step-by-step explanation:
Well, as you would be able to tell, you just have to find the LCM of 3 and 5. These do not have one before 3 x 5, so it is 15.
Let
be the weight of i-th player.
1. If the mean weight of 4 backfield members on the football team is 221 lb, then

2. If the mean weight of the 7 other players is 202 lb, then

3. From the previous statements you have that

Add these two equalities and then divide by 11:

Answer: the mean weight of the 11-person team is 
Answer:
(a) The ones that are equivalent to the given fraction are:
and 
(b) The one that is equivalent to the given fraction is: