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2 years ago

Which of the following is a solution to the inequality y>3x−9 ? (Select all that apply)

Mathematics

2 answers:

Alla [95]2 years ago

8 0

Answer:

necesitas pensar profesor porque todavía no entiendo bien si quieres

MrRa [10]2 years ago

4 0

Answer:

the answer

Step-by-step explanation:

y=77 since I am smart

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Please answer this correctly

attashe74 [19]

It is 0.2 x 0.4
The green part is 20 squares and the yellow part is 40 squares. The intersection has 8 squares which means the answer is 0.08

8 0

3 years ago

Solve -12 = z ÷ 3 for z. z =

mash [69]

Answer: z = −36

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

-12 = 1/3z

Step 2: Flip the equation.

1/3x = -12

Step 3: Multiply both sides by 3.

3* (1/3z) = (3) * (-12)

6 0

3 years ago

Read 2 more answers

The function g(x) = x2 is transformed to obtain function h: h(x) = g(x + 1).

Anika [276]

Good evening ,

Answer:

We just transform the g graph using a translation of vector (-i)

Step-by-step explanation:

Look at the photo below for the graphs.

5 0

3 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

------------------------------

$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

PLEASE HELP ME FIGURE OUT WHICH ONE I GOT WRONG, TYSMM :)

otez555 [7]

Answer:

da one in the middle and i do relize this is a test becuse i just took it.

Step-by-step explanation:

6 0

3 years ago