0^9 +7x+189yx−3y
o
9
+7x−3y
9
+7x+3y
9
−7x−3y
9
−7x+3y
9
+7x+189yx−3y
2 Collect like terms.
{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y
o
9
+(7x+7x−7x−7x+7x)+(−3y
9
+3y
9
−3y
9
+3y
9
)+189yx−3y
3 Simplify.
{o}^{9}+7x+189yx-3y
o
9
+7x+189yx−3y
Answer:
B 12
Step-by-step explanation:
- manuel ate 1/3X
- His brother ate 1/4X
- leftover is 5
- total is X
manuel+brother+leftover=X
x/3+x/4+5=x
7x+60/12=x
7x+60=12x
60=12x-7x
60=5x
x=60/5
x= 12
Answer:
131.95888888888888
Step-by-step explanation:
Your Welcome :)
Answer:
8.9 meters
Step-by-step explanation:
this seems like a problem where you can use the pythagorean theorem:
you know one of the two legs (6m) and the hypotenuse (9m), you must find the other leg
a^2 + 6^2 = 9^2
a^2 + 36 = 81
a^2 = 45
a =
or
·
which simplifies to be 3
or approx. 8.9 meters
What you gotta take from this problem:
What Joe got during break =

What his sister gave him =

What he has total = 10 tadpoles.
Now to assemble this equation:

Now combine like terms to get

Subtract 2 on each side of the equation to get

Now you would divide 5 on each side and get

, however since you can't have a .6 of a tadpole, you would have to round it up to 2.