This would be set up as: 6/ = 25/100
so we have to cross multiply 6*100= 600 then 600 divided by 25= 24
Therefore 24 is the answer.
The displacement is 18.03 steps, and the direction is 47.25°
<h3>
How to get the displacement?</h3>
We know that displacement is the difference between the final position and the initial position.
We assume the initial position (0, 0). Let's define the positive x-axis as the east and the positive y-axis as the north.
First, the student moves 8 steps east, so she is at:
(0 + 8, 0)
Then she moves 6 steps northeast, so the new position is:
(6*cos(45°) + 8, 6*cos(45°))
Finally, she moves 9 steps due north, so we have:
(6*cos(45°) + 8, 6*cos(45°) + 9)
Then the final position is:
(12.24, 13.24)
So the displacement is:
D = (12.24, 13.24) - (0, 0) = (12.24, 13.24)
The magnitude of the displacement is:

So the magnitude is 18.03 steps.
And the direction is given by the arctangent of the quotient between the y-component and the x-component:

If you want to learn more about displacements:
brainly.com/question/4931057
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Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11