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rjkz [21]
3 years ago
5

Do u know what 42 ÷____= 0.042 is I need help

Mathematics
1 answer:
Bingel [31]3 years ago
3 0

Answer:

1000

Step-by-step explanation:

Doing this on a calculator yields 1000.

Alternatively, do part or all of the problem in your head:

Rewrite 42 ÷____= 0.042 as


  42

------------

0.042

and move the decimal points 3 place to the right:

42 becomes 42000, and 0.042 becomes 42.  Thus, we have:

42000

------------ = 1000

    42

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Dmitriy789 [7]
The answer your question is A
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A “stick” object of height 10 cm is standing in front of a point X–ray source at a distance of 50 cm from the source. The detect
blagie [28]

Answer:

40 cm.

Step-by-step explanation:

Given,

height of the object = 10 cm

Distance of the object from the X-ray= 50 cm

Distance of detector from the source = 2 m = 200 cm

Height of the image, h = ?

Now,

\tan \theta = \frac{P}{B}

\tan \theta = \frac{10}{50}

\tan \theta = \frac{1}{5}

Again applying

\tan \theta = \frac{P}{B}

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6 0
3 years ago
Find the values of x and y
zhuklara [117]

You can use a tangent:

tangent=\dfrac{opposite}{adjacent}

We have opposite = 17 and adjacent = x.

\tan30^o=\dfrac{\sqrt3}{3}

substitute:

\dfrac{17}{x}=\dfrac{\sqrt3}{3}       cross multiply

x\sqrt3=(3)(17)     multiply both sides by √3

x(\sqrt3)(\sqrt3)=51\sqrt3

3x=51\sqrt3      divide both sides by 3

x=17\sqrt3

Use the Pythagorean theorem:

y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34

-------------------------------------------------------------------------------------------------

Other method.

30^o-60^o-90^o triangle.

The sides are in the ratio 1:2:\sqrt3\to17:y:x

Therefore

17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3

 


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1) Find the x-coordinate of the vertex, y-coordinate of the vertex, and the z-
Afina-wow [57]

Answer:

b is the answer i think

Step-by-step explanation:

I learned this at some point

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3 years ago
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