Answer:
80 < 93 < 121 < 127
Step-by-step explanation:
For a geometric series,

Formula to be used,
Sum of t terms of a geometric series = 
Here t = number of terms
a = first term
r = common ratio
1). 
First term of this series 'a' = 3
Common ratio 'r' = 2
Number of terms 't' = 5
Therefore, sum of 5 terms of the series = 
= 93
2). 
First term 'a' = 1
Common ratio 'r' = 2
Number of terms 't' = 7
Sum of 7 terms of this series = 
= 127
3). 
First term 'a' = 1
Common ratio 'r' = 3
Number of terms 't' = 5
Therefore, sum of 5 terms = 
= 121
4). 
First term 'a' = 2
Common ratio 'r' = 3
Number of terms 't' = 4
Therefore, sum of 4 terms of the series = 
= 80
80 < 93 < 121 < 127 will be the answer.
(-2a^5b^4) * (42ab^6) = -84a^6b^10
Interquartile Range is the answer
Hope this helps you just follow these steps
Answer:
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