Regular hexagon consists of six equilateral triangles. The angle of a hexagon is equal to the sum of two angles in an equilateral triangle.
I believe that the answer is C
BISECTOR OF AN ANGLE
Slope is 3 so the equation is y-2=3(x-1) in point slope form as y-y1 =m (x-x1)
Using the law of sines, it is found that 1 triangle can be formed with the given conditions.
<h3>What is the law of sines?</h3>
Suppose we have a triangle in which:
- The length of the side opposite to angle A is a.
- The length of the side opposite to angle B is b.
- The length of the side opposite to angle C is c.
The lengths and the sine of the angles are related as follows:

Hence, for this problem, we have that the relation is:




G = 54º
A triangle can have one angle of 64º and another of 54º, hence 1 triangle can be formed with the given conditions.
More can be learned about the law of sines at brainly.com/question/25535771
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Answer:
First, we know that the area of a rectangle of width W and length L is:
A = W*L
In the case of Roberto's plan, we can see that the length of the whole rectangle is:
L = 1.5ft + x + 1.5ft = 3 ft + x
And the width is:
W = 3ft + x + 3ft = 6ft + x
Then the area of the whole thing is:
A = (3ft + x)*(6ft + x)
This is what we wanted, a product of two polynomials that represents the area of Roberto's plot.
Now if we subtract the white square (is a square of sidelength x, then its area is A = x*x) we will get the area of the border;
The total area of Roberto's borders is:
Area of the border = (3ft + x)*(6ft + x) - x*x
= 3ft*6ft + 3ft*x + x*6ft + x^2 - x^2
= x*9ft + 18ft^2