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expeople1 [14]
3 years ago
8

What are the coordinates of the circumcenter of a triangle with vertices A(−1, 1) , B(5, 1) , and C(−1, −1) ?

Mathematics
1 answer:
Elina [12.6K]3 years ago
7 0
Triangle ABC is a right triangle with vertex A containing the right angle.

You can tell because AB is a horizontal line since A and B have the same y-coordinate, and AC is a vertical line since A and C have the same x-coordinate.

A right triangle in a circumcircle is always in the semicircle, with the centre of the circle lying in the middle of the side opposite the right angle.

So, the circumcenter is the midpoint of BC.

The midpoint of BC is ((5-1)/2, (1-1)/2) = (2, 0)
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Olin [163]

Answer:

y = 6x

Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant pf proportionality

Here k = 6 , then

y = 6x ← equation of proportion

7 0
3 years ago
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Answer:

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20 people show up to the party, and Robert decides to give them each the same
nadya68 [22]

Answer:

depends on how much pizza he has.

Step-by-step explanation:

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8 0
2 years ago
The average of 4, 9, 16, 25 and x is 2x. What is the value of x? A) 4 B)6 A)9 C)9 D)12
Elodia [21]
The average of 4, 9, 16, 25 and x is 2x means that;
(4+9+16+25+x)/5=2x
Multiply both side by 5
5(54+x)/5=2x(5)
54+x=10x
Subtract x to both side
54+x-x=10x-x
54=9x
Divided 9 to both side
54/9=9x/9
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Check:
Substitute x with 6
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60/5=12
12=12; so x=6 which marks B as the correct answer. Have a nice day!
5 0
3 years ago
HELP! Identify the equation of the circle that has its center at (-3, -4) and passes through the origin.
Lunna [17]

Answer:

Option B. (x+3) ^2+(y+4)^2=25

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

(x-h)^{2}+(y-k)^{2}=r^{2}

where

(h,k) is the center and r is the radius

step 1

Find the radius of the circle

Remember that the distance of the center and any point on the circle is equal to the radius of the circle

so

Find the distance between the points (-3,-4) and (0,0)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute

r=\sqrt{(0+4)^{2}+(0+3)^{2}}

r=\sqrt{(4)^{2}+(3)^{2}}

r=\sqrt{25}

r=5\ units

step 2

Find the equation of the circle

(x-h)^{2}+(y-k)^{2}=r^{2}

the center is the point (-3,-4) and the radius is r=5 units

substitute

(x+3)^{2}+(y+4)^{2}=5^{2}

(x+3)^{2}+(y+4)^{2}=25

6 0
3 years ago
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