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enyata [817]
2 years ago
12

Y=−2x+4 when y equals -2 what is x? PLZ HELP URGENT!

Mathematics
1 answer:
statuscvo [17]2 years ago
5 0

Answer:

x=3

Step-by-step explanation:

turn y to -2. move the 4 over to get -6 on the left side. divide both sides by -2 to get 3=x. x is 3.

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Simplify: (5x2 - 3x - 4)(3x - 7) A. 15x3 - 44x2 + 9x - 28 B. 15x3 - 44x2 + 9x + 28 C. 15x3 + 26x2 - 33x - 28 D. 15x3 - 26x2 - 33
pochemuha

Answer:

A. 15x^3 -44x^2 +9x +28

Step-by-step explanation:

(5x^2 -3x -4)(3x - 7)

first, distribute by multiplying the terms in each parenthesis with each other:

(5x^2 * 3x) - (3x * 3x) - (4 * 3x) - (5x^2 * 7) + (3x * 7) + (4 * 7)

simplify:

15x^3 -35x^2 -9x^2 +21x -12x +28

Now combine like terms:

15x^3 -44x^2 +9x +28

8 0
3 years ago
50 POINTS. A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t)=
Morgarella [4.7K]

Answer:

The domain that makes sense for this function is all values greater than or equal to 0.

Step-by-step explanation:

A ball is thrown into the air from a height of 4 feet at time <em>t</em> = 0. It is modeled by the function:

h(t)=-16t^2+64t+4

The domain of the function is time <em>t</em>. The range of the function is the ball's height in the air <em>h</em>.

Since time is our domain, we must restrict our domain to values equal to or greater than 0 since time cannot be negative.

Therefore, the domain that makes sense for this function is all values greater than or equal to 0.

In interval notation, this is:

[0, \infty)

And as an inequality:

t\geq 0

7 0
3 years ago
Read 2 more answers
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snow_lady [41]

f(x)=2x^2+0x-5

Find the vertex

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Input x into the equation to find y or f(x)

0+0-5=f(x)

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Now find a random x coordinate to input into the equation.

Let's do 4.

32+0-5=f(x)=27

It may not look like a parabola due to it being uneven.

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3 years ago
Which of the following graphs is the inverse of f(x) = x2 + 4?
Eddi Din [679]

Answer:

Step-by-step explanation:

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3 years ago
Find the Value of a and b i dare u​
fenix001 [56]

Well it's a dare so I guess I'll do it.

3 0
3 years ago
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