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3 years ago

Someone plz help me with this???

Mathematics

1 answer:

Travka [436]3 years ago

7 0

Since LON is a straight angle, it equals 180 degrees. That makes LOM and MON supplementary angles. Thus, we know (7x-92) + (6x+12) = 180. Since both are positive, we can drop the parentheses.
7x - 92 + 6x + 12 = 180
Simplify: 13x - 80 = 180
Add 80 to both sides: 13x = 260
Divide both sides by 13: x = 20
Plug in: 7(20)-92
140 - 92
LOM is 48 degrees.

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2 years ago

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

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$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$

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6 0

2 years ago

Read 2 more answers

Solve for x:

pentagon [3]

Answer:

2<x<3

Step-by-step explanation:

4x-4<8 AND 9x+5>23

Solve the first inequality

4x-4<8

Add 4 to each side

4x-4+4 <8+4

4x<12

Divide by 4

4x/4 <12/4

x <3

Solve the second inequality

9x+5>23

Subtract 5 from each side

9x+5-5>23-5

9x >18

Divide by 9

9x/9>18/9

x>2

Put together

x<3 and x>2

2<x<3

3 0

3 years ago

Any help would be great . Thank you!

vladimir1956 [14]

X = 4 and Y = 9. I did a complicated way of doing it so if u copy it it would look weird

3 0

2 years ago