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miss Akunina [59]

3 years ago

10

Laptop computers are measured according to the diagonals of their screens. A 16-inch laptop has a screen that is 7 inches tall.

How wide is the screen?

1 answer:

disa [49]3 years ago

6 0

Approximately 14.4 inches I think is the correct answer!

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kirza4 [7]

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Determine whether each integral is convergent or divergent. If it is convergent evaluate it. (a) integral from 1^(infinity) e^(-

AVprozaik [17]

Answer:

a) So, this integral is convergent.

b) So, this integral is divergent.

c) So, this integral is divergent.

Step-by-step explanation:

We calculate the next integrals:

a)

$\int_1^{\infty} e^{-2x} dx=\left[-\frac{e^{-2x}}{2}\right]_1^{\infty}\\\\\int_1^{\infty} e^{-2x} dx=-\frac{e^{-\infty}}{2}+\frac{e^{-2}}{2}\\\\\int_1^{\infty} e^{-2x} dx=\frac{e^{-2}}{2}\\$

So, this integral is convergent.

b)

$\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\$

So, this integral is divergent.

c)

$\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\$

So, this integral is divergent.

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3 years ago

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netineya [11]

Sorry the question you typed is kinda messy. But I see you have typed “23* 26” I’m gonna assume you’re asking which postulate or theorem is angle 2 and angle 3, and angle 2 and angle 6. So angle 2 and 3 are vertical angles. Angle 2 and 6 are corresponding angles. If that wasn’t what you wanted, please let me know in the comments so I can understand your problem clearly and solve it.

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2 years ago

Type a digit that makes this statement true.<br><br> 17,421,55<br> is divisible by 6.

Anettt [7]

Answer:

<h2>290359.166667</h2>

Step-by-step explanation:

17,421,55/6=290359.166667

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2 years ago

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