PLS HELP ME WITH THIS

GarryVolchara [31]

Answer:

X is 36 and y is 48.

Step-by-step explanation:

So a couple of things here: both triangles are equal, and triangles always add up to 180 degrees. If we do some math:

180-108-48=24

This means that 2x-y needs to equal 24. We know what y is, it's 48 since both triangles are equal. Lets do some more math to find x.

48+24=72

72 divided by 2 = 36. 36 is the answer for x.

7 0

2 years ago

A ship leaves port at 1:00 pm and travels Upper N 70 degrees Upper WN70°W at the rate of 10 mph. Another ship leaves the same p

Leni [432]

Answer:

30.4 miles

Step-by-step explanations:

Please refer to the attached image for explanations

7 0

3 years ago

Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of

frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

3) $\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

4) $df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 21 37 58 116

Not Married 59 63 42 164

Total 80 100 100 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is $\alpha=0.05$

Part 2

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{80*116}{280}=33.143$

$E_{2} =\frac{100*116}{280}=41.429$

$E_{3} =\frac{100*116}{280}=41.429$

$E_{4} =\frac{80*164}{280}=46.857$

$E_{5} =\frac{100*164}{280}=58.571$

$E_{6} =\frac{100*164}{280}=58.571$

And the expected values are given by:

Diag. Alcoholic Undiagnosed Alcoholic Not alcoholic Total

Married 33.143 41.429 41.429 116

Not Married 46.857 58.571 58.571 164

Total 80 100 100 280

And now we can calculate the statistic:

$\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72$

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

7 0

3 years ago

A worker at a mill is loading 10-lb bags of flour into boxes to deliver to a local warehouse. Each box holds 4 bags of flour. If

Hunter-Best [27]

Answer: 100 boxes

Step-by-step explanation:

Hi, since 1 ton = 2,000 lbs

We have to divide 10lbs by 2000 to convert the lbs in tons.

1t/2000lb = xt / 10lb

10 /2000=0.005

0.005 ton = 10 lbs (1 bag)

Each box has 4 bags

0.005 ton x 4 = 0.02 ton

So each box weights 0.02 ton

Since we need 2 tons.

Using proportions:

0.02t/1 box= 2 t / x boxes

x = 2 / (0.02/1)

x = 100 boxes

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Solve the system by the elimination method.

joja [24]

Answer: B

Step-by-step explanation:

YOU MINUS 4 -4 WHICH IS -8 SO ITS B

8 0

3 years ago

Read 2 more answers