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natima [27]
3 years ago
9

One night the king couldn't sleep, so he went down into the royal kitchen, where he found a bowl full of mangoes. being hungry,

he took 1/6 of the mangoes. later that same night, the queen was hungry and couldn't sleep. she, too, found the mangoes and took 1/5 of what the king had left. still later, the first prince awoke, went to the kitchen, and ate 1/4 of the remaining mangoes. even later, his brother, the second prince, ate 1/3 of what was then left. finally, the third prince ate 1/2 of what was left, leaving only three mangoes for the servants. how many mangoes were originally in the bowl? is there more than one solution?
Mathematics
1 answer:
Ksju [112]3 years ago
6 0
If you think in picture, it will be easier
1. king --1/6 of all
2. queen -- 1/5 of what king had left (remaining)
3. 1st prince -- 1/4 of remaining
4. 2nd prince -- 1/3 of remaining
5. 3 rd prince -- 1/2 of remaining
6. there are 3 mangoes left

so if we think that there are 6 parts of all
1. king took 1st part (5 parts left)
2. queen took 1 of what king had left which he left 5 parts (4 parts left)
3. 1st prince took 1 of 4 (3 parts left)
4. 2nd prince took 1 of 3 (2 parts left)
5. 3rd prince took 1 of 2 (1 part left)
that means 1 part equals 3 mangoes
so we have 6 parts at first then there were 18 mangoes originally in the bowl.

i think there is only 1 answer.
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Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

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Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

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On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

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In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

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t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

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p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

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Someone please help as soon as possible
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Answer:i believe it is the first answer

Step-by-step explanation:

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