If you could send an image that is clearer I will be able to help you more, but for what we have: 3y+13=5y-5, the answer would be 2y=18 (after doing all your algebra). Then you would divide both sides by 2 and get y=9. After this you can plug in 9 for every y and find the angles/measures of all sides!
Hope this helped, and if you need any further assistance, please let me know!
F1 = 6*cos(30) i + 6*sin(30) j = 5.20 i + 3 j
<span>F2 = 0 i + 5 j </span>
<span>R = F1 + F2 </span>
<span>Add the 'i's together (x direction) and the 'j's together (y direction) </span>
<span>R = (5.20 + 0) i + (3 + 5) j = 5.2 i + 8 j </span>
<span>Magnitude: </span>
<span>||R|| = </span>√<span>(5.2^2 + 8 ^2) = </span>√<span>91 = 9.54 </span>
<span>Direction: </span>
Θ<span> = atan ( Rj / Ri ) = atan( 8 / 5.2 ) = 57.0</span>⁰
5x10^9
Just find out how many zeros there are
The values of the letters in coordinates (a, b) and (c,d) are;
<u><em>a = -4</em></u>
<u><em>b = -6</em></u>
<u><em>c = 2</em></u>
<u><em>d = 6</em></u>
<u><em /></u>
We are given two equations;
-6x + 3y = 6 ---(eq 1)
x² + y = 10 ---(eq 2)
- We are told that they intersect at coordinates; (a, b) and (c, d).
Let us make y the subject in eq 2 to get;
y = 10 - x² --(eq 3)
- Let us put 10 - x² into eq 1 to get;
-6x + 3(10 - x²) = 6
expanding further gives;
-6x + 30 - 3x² = 6
rearranging gives;
3x² + 6x - 24 = 0
Using online quadratic equation <em>solver</em>, we have;
x = -4 and x = 2
Putting x = -4 into eq 3 gives;
y = 10 - (-4)²
y = 10 - 16
y = -6
Putting x = 2 into eq 3 gives;
y = 10 - (2)²
y = 10 - 4
y = 6
- Thus, the coordinates are; (-4, -6) and (2, 6)
Comparing with (a, b) and (c,d), we have;
a = -4
b = -6
c = 2
d = 6
Read more at; brainly.com/question/15165519
