Answer:
Horizontal line: y=-5
Vertical line: x = 4
Step-by-step explanation:
As we have to determine the equations for the horizontal and vertical lines passing through the point (4, -5).
- To determine the equation for the horizontal line passing through the point (4, -5), we must observe that the horizontal line will always have the same y-value regardless of the x-value.
Therefore, the equation of the horizontal line passing through the point (4, -5) will be: y=-5
- To determine the equation for the vertical line passing through the point (4, -5), we must observe that the vertical line will always have the same x-value regardless of the y-value.
Therefore, the equation of the vertical line passing through the point (4, -5) will be: x=4
Hence:
Horizontal line: y=-5
Vertical line: x = 4
Equating the formula (d is the diameter)
d^2/4 = 132.7
d^2 = 132.7*4/
d =
d = 13.0017147331
d= 13cm
Answer:
x = 2, y = 7, z = 12
Step-by-step explanation:
x + y - z = -3 (1)
3x - y + z = 11 (2)
x - 4y + z = -14 (3)
add (1) and (2)
4x = 8 x = 2
add (1) and (3)
2x - 3y = -17
2(2) - 3y = -17
-3y = -17 - 4
-3y = -21
y = 7
Find z using any equation
x + y - z = -3
2 + 7 - z = -3
9 - z = -3
z = 12
Answer:
the value of a, if points A and D belong to the x−axis and m∠BAD=60 degrees is 2/√3
Step-by-step explanation:
Trapezoid ABCD with height 2 unit contain Points A and D which may be A(-1,0) and D(5.0)
Vertex of parabola is the point where parabola crosses its axis
Let suppose A and D are two points then draw altitude on them CE where C is on AD
As height of altitude has been given that is 2 then
total angle = 180 degrees
m∠BAD=60 degrees
m∠CEA =180 - 60 -90
= 30
then the value for AE = 2/√3.
y=a(x+1)(x−5).
where 2/√3 is right of -1 and 2 unit above x-axis
Answer:
It is ................................................................. 1
Step-by-step explanation:
