Answer:
See explanartions below
Step-by-step explanation:
Given the coordinates A(-6,3) B(0,5) C(2,-1)
We first need to get the slope of AB, BC and AC
For AB;
A(-6,3) B(0,5)
Mab = 5-3/0-(-6)
Mab = 2/6
Mab = 1/3
For BC;
B(0,5) C(2,-1)
Mbc = -1-5/2-0
Mbc = -6/2
Mc = -3
For AC:
A(-6,3) C(2,-1)
Mac = -1-3/2-(-6)
MAc = -4/8
Mac = -1/2
Taking the product of Mab and Mbc
Mab * Mbc = 1/3 + -3
Mab * Mbc = -1
<em>Since the product of Mab and Mbc is -1, hence AB abd BC are perpendicular showing that one of the angle of triangle ABC is 90 degrees</em>
The original answer for that question would be 303.55. The best estimate when you round to the nearest tenth the approximate answer would be 303.6 because the 5 in the hundredths place rounds the 5 in the tenths place to a 6. So the approximate answer would be 303.6....hope this helps.
Answer:
A
Step-by-step explanation:
What we need to know simply is the time taken for both trips. We know the car spent 6 hours on the first leg, that is settled.
What we do not know is the time spent on the second leg. To get the time spent on the second leg of the journey, we only need to get the total distance divided by the speed.
We can get the distance using the first part of the question. The time is 6 hours and the speed is x miles per hour, the total distance is this 6x miles.
Now we need to know the time spent on the second leg of the journey. We know that the distance is the same. Hence the time spent is 6x/y where y is the speed for the second leg and 6x is the length of each leg
Now the total time spent is thus (6x/y +6) hours. We need to however convert this to minutes. We do this by multiplying by 60
(6x/y + 6) * 60
Answer:
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Step-by-step explanation:
