Answer:
11.82
Step-by-step explanation: I know this because 21.32-9.50= 11.82
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
Hope this helped, Hope I did not make it to complated
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Answer:
The initial amount a = 1
The growth or decay factor = 0.01025
Step-by-step explanation:
The exponential function.
y = 0.01025^x
The initial amount a = 1
The growth or decay factor = 0.01025
The exponential equation can be rewritten as Y = 1(0.01025)^x
