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Andre45 [30]
3 years ago
11

Algebra expression 5 minus the difference of m and 2?

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

7-m

Step-by-step explanation:

The difference of m and 2

m-2

5 minus the difference of m-2

5-(m-2)

5-m+2

Collect like terms

7-m

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What is 4^6 . 4^6 please help​
KonstantinChe [14]

Answer:

4^12 or 16777216

Step-by-step explanation:

4^6* 4^6

We can symplify 4^6* 4^6

Since they both have the same base, we can add there exponent:

4^6* 4^6= 4^12

4^12 equals to 16777216

8 0
3 years ago
Given g(x)=Squareroot x-4 and h(x)=2x-8, what is g(h(10))
yan [13]

Answer:

g(h(10)) = 2\sqrt 2

Step-by-step explanation:

Given

g(x) = \sqrt {x - 4

h(x) = 2x - 8

Required

g(h(10))

First, calculate g(h(x))

We have:

g(x) = \sqrt {x - 4

This gives:

g(h(x)) = \sqrt {h(x) - 4

Substitute h(x) = 2x - 8

g(h(x)) = \sqrt {2x - 8 - 4

g(h(x)) = \sqrt {2x - 12

Substitute x = 10

g(h(10)) = \sqrt {2*10 - 12

g(h(10)) = \sqrt {20 - 12

g(h(10)) = \sqrt {8\\

Split

g(h(10)) = \sqrt {4} * \sqrt 2

This gives

g(h(10)) = 2\sqrt 2

8 0
3 years ago
Read 2 more answers
P(7, - 2); y= 7x+4= 4<br><br><br> PLEASE HELP
Mars2501 [29]

Answer:

x= - 16

Step-by-step explanation:

substitute y=0 then multuply both sides move the variable to the left and change the sign.

3 0
3 years ago
Original price $65.00; Markdown: 12%
MAVERICK [17]
65 x .12 = 7.865 - 7.8 = 57.2

8 0
3 years ago
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
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