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3 years ago

Given f(x) = x - 7 and g(x) = x2 Find g({4)). g(f{4)) =

Mathematics

1 answer:

maksim [4K]3 years ago

3 0

Answer:

g({4)). g(f{4)) = 144

Step-by-step explanation:

Given f(x) = x - 7 and g(x) = x^2 Find g({4)). g(f{4)) =

g(4) = 4^2 = 16

g(f(4)) = (4 - 7)^2 = 9

g({4)). g(f{4)) =16 * 9 = 144

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Righty in equation in standard form using integers Y +1 equals 2/3 parentheses X +3 parentheses

Korolek [52]

Answer:

The standard for of the equation would be 2x + 3y = 3

Step-by-step explanation:

To start, we simply need to solve for the constant.

y + 1 = 2/3(x + 3)

y + 1 = 2/3x + 2

2/3x + y + 1 = 2

2/3x + y = 1

Now we need to multiply all the numbers by the largest denominator. This will make all the numbers integers. In this case, that number would be 3.

2x + 3y = 3

4 0

4 years ago

An insurance company offers its policyholders a number of different premium payment options. For a randomly selected policyholde

n200080 [17]

Answer:

(a)

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

(b)

$P(3 \le x \le 6) = 0.30$

$P(4 \le x)=0.60$

Step-by-step explanation:

Given

$F(x) = \left[\begin{array}{ccc}0& x$

Solving (a): The pmf

This means that we list out the probability of each value of x.

To do this, we simply subtract the current probability value from the next.

So, we have:

$\begin{array}{cccccc}x & {1} & {3} & {4} & {6} & {12} \ \\ P(x) & {0.30} & {0.10} & {0.05} & {0.15} & {0.40} \ \end{array}$

The calculation is as follows:

$0.30 - 0 = 0.30$

$0.40 - 0.30 = 0.10$

$0.45 - 0.40 = 0.05$

$0.60 - 0.45 = 0.15$

$1 - 0.60 = 0.40$

The x values are gotten by considering where the equality sign is in each range.

$1 \le x < 3$ means $x = 1$

$3 \le x < 4$ means $x = 3$

$4 \le x < 6$ means $x=4$

$6 \le x < 12$ means $x = 6$

$12 \le x$ means $x = 12$

Solving (b):

$(i)\ P(3 \le x \le 6)$

This is calculated as:

$P(3 \le x \le 6) = F(6) - F(3-)$

From the given function

$F(6)= 0.60$

$F(3-) = F(1) = 0.30$

So:

$P(3 \le x \le 6) = 0.60 - 0.30$

$P(3 \le x \le 6) = 0.30$

$(ii)\ P(4 \le x)$

This is calculated as:

$P(4 \le x)=1 - F(4-)$

$P(4 \le x)=1 - F(3)$

$P(4 \le x)=1 - 0.40$

$P(4 \le x)=0.60$

8 0

3 years ago

Please help!!!!!!!!!!

Degger [83]

I hope this helps you

4 0

3 years ago

Patrick has just finished building a pen for his new dog. The pen is 3 feet wider than it is long. He also built a doghouse to p

zalisa [80]

General Idea:

(i) Assign variable for the unknown that we need to find

(ii) Sketch a diagram to help us visualize the problem

(iii) Write the mathematical equation representing the description given.

(iv) Solve the equation by substitution method. Solving means finding the values of the variables which will make both the equation TRUE

Applying the concept:

Given: x represents the length of the pen and y represents the area of the doghouse

Statement 1: "The pen is 3 feet wider than it is long"

$Length \; of\; the \; pen = x\\ Width \; of\; the\; pen=x+3$

------

Statement 2: "He also built a doghouse to put in the pen which has a perimeter that is equal to the area of its base"

$Area \; of\; the\; Dog \; house=y\\ Perimeter \; of\; Dog\; house=y$

------

Statement 3: "After putting the doghouse in the pen, he calculates that the dog will have 178 square feet of space to run around inside the pen."

$Area \; of \; the\; Pen - Area \;of \;the\;Dog \;House=\;Space\;inside\;Pen\\ \\ x \cdot (x+3)-y=178\\ Distributing \;x\;in\;the\;left\;side\;of\;the\;equation\\ \\ x^2+3x-y=178\Rightarrow\; 1^{st}\; Equation\\$

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Statement 4: "The perimeter of the pen is 3 times greater than the perimeter of the doghouse."

$Perimeter\; of\; the\; Pen=3\; \cdot \; Perimeter\; of\; the\; Dog\; House\\ \\ 2(x \; + \; x+3)=3 \cdot y\\ Combine\; like\; terms\; inside\; the\; parenthesis\\ \\ 2(2x+3)=3y\\ Distribute\; 2\; in\; the\; left\; side\; of\; the\; equation\\ \\ 4x+6=3y\\ Subtract \; 6\; and \; 3y\; on\; both\; sides\; of\; the\; equation\\ \\ 4x+6-3y-6=3y-3y-6\\ Combine\; like\; terms\\ \\ 4x-3y=-6 \Rightarrow \; \; 2^{nd}\; Equation\\$