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sveticcg [70]
3 years ago
12

Write an equation for the line parallel to the given line that contains point C

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0
   y - y₁ = m(x - x₁)
y - (-3) = ¹/₂(x - (-4))
   y + 3 = ¹/₂(x + 4)
   y + 3 = ¹/₂(x) + ¹/₂(4)
   y + 3 = ¹/₂x + 2
       - 3           - 3
         y = ¹/₂x - 1
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In the diagram, JOK and MON are straight lines. Angle NOP and Angle NOQ are complimentary angles. Calculate the value of x - y.
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Answer:

x - y = 118

Step-by-step explanation:

Since ∠ NOP and ∠ NOQ are complimentary then ∠ POQ = 90°

Since JOK is a straight line then

∠ JOP + ∠ POQ + ∠ QOK = 180 , that is

76 + 90 + y = 180

166 + y = 180 ( subtract 166 from both sides )

y = 14

Since MON is a straight line then

∠ MOK + ∠ KOQ + ∠ QON = 180, that is

x + 14 + 34 = 180

x + 48 = 180 ( subtract 48 from both sides )

x = 132

Thus

x - y = 132 - 14 = 118

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