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3 years ago

PLEASE HELP, THIS IS REALLY IMPORTANT. PLEASE ANSWER ASAP.

Mathematics

1 answer:

Assoli18 [71]3 years ago

8 0

Yes the diagonals of a parallelogram have the same midpoint since they ... of the intersection of the diagonals of parallelogram AB CD given the vertex points ... If a parallelogram is a rhombus then its diagonals are? , statement 2 is the answer

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Simplify the expiration 2h+6h+4h

dezoksy [38]

Answer:

I think the answer is12h?

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2 years ago

The square root of which of the following integers is between 7 and 8

pashok25 [27]

Answer:

the square root of 50 and 60

Step-by-step explanation:

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3 years ago

Read 2 more answers

Are the following lines parallel? <br><br> y = -3x + 1 <br><br> y = 4 - 3x

PIT_PIT [208]

Answer:

Simple! The answer is yes.

Step-by-step explanation:

Simply put the equations into Desmos graphing calculator and it will show you that the equations are parallel. :))

4 0

2 years ago

The point-slope form of the equation of a line that passes through points (8,4) and (0, 2) is y-

Oksi-84 [34.3K]

For this case we have that by definition, the equation of a line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

While the point-slope equation of a line is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: It's the slope

$(x_ {0}, y_ {0}):$ It is a point through which the line passes

In this case we have a line through:

(8,4) and (0,2)

Therefore, its slope is:

$m = \frac {2-4} {0-8} = \frac {-2} {- 8} = \frac {1} {4}$

Its point-slope equation is:

$y-4 = \frac {1} {4} (x-8)$

Then, we manipulate the expression to find the equation of the slope-intersection form:

$y-4 = \frac {1} {4} x- \frac {8} {4}\\y-4 = \frac {1} {4} x-2\\y = \frac {1} {4} x-2 + 4\\y = \frac {1} {4} x + 2$

Therefore, the cut-off point with the y-axis is $b = 2$

ANswer:

$y = \frac {1} {4} x + 2$

7 0

3 years ago

MARK AS BRAINLEST

WARRIOR [948]

Answer:

{- 2, - 4, - 6, - 8, - 10 }

Step-by-step explanation:

Given

f(x) = 2x - 6 with domain { - 2, - 1, 0, 1, 2 }

To obtain the range substitute the values of x from the domain into f(x)

f(- 2) = 2(- 2) - 6 = - 4 - 6 = - 10

f(- 1) = 2(- 1) - 6 = - 2 - 6 = - 8

f(0) = 2(0) - 6 = 0 - 6 = - 6

f(1) = 2(1) - 6 = 2 - 6 = - 4

f(2) = 2(2) - 6 = 4 - 6 = - 2

Range is { - 2, - 4, - 6, - 8, - 10 }

6 0

3 years ago