100 notes were altogether
<em><u>Solution:</u></em>
Given that ratio of the number of $2 notes to the number of $5 notes was 4 : 1
number of $2 notes : number of $5 notes = 4 : 1
Let 4x be the number of $ 2 notes
Let 1x be the number of $ 5 notes
Given that total value of notes is $ 260
Therefore,
$ 2 (number of $ 2 notes ) + $ 5(number of $ 5 notes ) = $ 260
$ 2(4x) + $ 5(1x) = $ 260
8x + 5x = 260
13x = 260
x = 20
<em><u>Thus number of notes altogether is given as:</u></em>
4x + 1x = 4(20) + 1(20) = 80 + 20 = 100
Thus 100 notes were altogether
Answer:
<h2>46•18</h2>
Step-by-step explanation:
<h3> I=PRT/100</h3><h2> 6740×<u>1</u><u>0</u>×7</h2><h2> 100</h2><h2> 674×1×7</h2><h2> 4618</h2><h2>the nearest hundredth is a 46•18 this is my answer</h2>
Answer:
a) 151lb.
b) 6.25 lb
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
In this problem, we have that:
So
a) The expected value of the sample mean of the weights is 151 lb.
(b) What is the standard deviation of the sampling distribution of the sample mean weight?
This is 
10x+20y=540
x+y=34
y=34-x
Plug in (34-x) for y:
10x+20(34-x)=540
10x+680-20x=540
-10x=-140
10x=140
x=14
There were 14 ten cent coins and 20 20 cent coins
