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3 years ago

8

Here Is My Last Question I Took A Snip Of 30 Points

1 answer:

coldgirl [10]3 years ago

7 0

Answer:

u did change it

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Please help with this!!

lozanna [386]

Answer:

#1.---60% #2.---$12.60 per hour

Step-by-step explanation:

#1. Since It was originally $50 you have 50% already, so what I did was I multiplied 50 by 2. this got me 100 which is a simpler way to calculate by. 50 to 80 dollars is a $30 change, so multiply that by 2 and you get 60. 60 will be your percent of change. You can double check this by multiplying 50 by .60, the answer will be 30 and 50+30=80

#2 Since Tyler starts off with $12 per hour with a 5% increase you will need to multiply 12*.05 this will get you the answer of 0.6 you then need to add $12, since that was his original payment. 12+0.6=12.60, so his final payment would by $12.60 per hour

5 0

3 years ago

The rational number that expresses a loss of $25.30 is +$25.30 -$25.30 +$2.53 -$2.53 , and the rational number that represents a

Mkey [24]

It’s the 2nd one I hope this helps homie

7 0

3 years ago

Read 2 more answers

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

An initial investment of $100 is now valued at $150. The annual interest rate is 5%, compounded continuously. The equation 100e0

fenix001 [56]

Answer:

8

Step-by-step explanation:

edg

8 0

3 years ago

Read 2 more answers

The function f(x) = |xl is graphed over the interval (-6,3].

garri49 [273]

Answer: g(x) = |x − 3|

Step-by-step explanation:

i got it right on edge. I hope this helps :D

4 0

3 years ago