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Lelu [443]
3 years ago
12

In right triangle ABC with the right angle at C, sin A= 2x + .1 and cos B = 4x - .7. Determine and state the vaule of x.

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
3 0
Imagine \angle A at the top of the triangle and \angle B at the bottom. (or used the attached picture for reference)

\sin A= \frac{opposite}{hypotenuse}

\cos B = \frac{adjacent}{hypotenuse}

One thing to note, however, is that the side opposite \angle A is the same side as the one adjacent to \angle B! Thus \sin A=\cos B.

Substitute these values for 2x+0.1 and 4x-0.7 and solve.

 4x-0.7=2x+0.1 \\ 4x=2x+0.8 \\ 2x=0.8\\ \boxed{x=0.4}

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