You said that (xy) = 16, and (x+y) = 4 .
From the second equation you can get [ x = 4 - y ],
then substitude that for 'x' in the first equation, and
finally, rearrange the first equation to read
<u>x² - 4x + 16 = 0</u>
Don't even try to factor that quadratic equation. Go straight
to the quadratic formula, and the two solutions you find are ...
<em>x = 2 + i 2√3</em>
and
<em>x = 2 - i 2√3</em> .
Those are the two number that do what you want.
There are no <u>real</u> numbers that can do it.
example: the line is y = ax + b
The line go through 2 points ( -4 ; 0 ) and ( 0 ; -2 )
So:
- -2 = 0a + b => b = -2
- 0 = -4a + (-2) => a = 2/-4 = -1/2
The line is y = -1/2x - 2 ( i'm not sure)
Answer: a
Ok done. Thank to me :>
To find the midpoint of a line use the midpoint formula which is M = (x1+x2/2 , y1 +y2/2) After plugging in the coordinates for your variables you should get (-1+5/2, -1+2/2) This simplifies to (2, 1/2) which is the coordinates for the middle point of the base XY.
V=4/3π r^3
(3/4)V=π r^3
3V/4π = r^3
third root√(3V/4π)
<span><span>Hope this helps!
</span>and May the Force Be With You
</span><span>
-Jabba</span>
Answer:
addison all the way
Step-by-step explanation:
