About 60% of the human body is water. At this rate, how many pounds of water are in the body of a 95-pound person?

2 answers:

7 0

95 = 95% = $\frac{unknown}{95}$
60% = $\frac{60}{100}$
$\frac{60}{100} = \frac{3}{5}$
You get $\frac{3}{5}$ by dividing the numerator and denominator of $\frac{60}{100}$ both by 12.
Next
$\frac{unknown}{95}$ ÷ $\frac{3}{5}$ = $\frac{57}{95}$ ÷ $\frac{3}{5}$
You get $\frac{57}{95}$ because you know that the denominator, 5, gets to 95 by multiplying it by 19. You multiply the numerator, 3, by 19 to get 57.
ANSWER:
57 pounds of water

alexdok [17]2 years ago

4 0

57 hope it helps you out

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