You can first take out an x^2 from each number , 3x^6 - 39x^4 + 108x^2 = x^2 ( 3x^4 - 39x^2 + 108) Then just factor and solve for the zero's of the equation
Answer:
g(1) = -65; g(n) = g(n-1) -15
Step-by-step explanation:
Using n = 1, 2, 3, we can find the first three terms of the sequence:
g(1) = -50 -15 = -65
g(2) = -50 -15(2) = -80
g(3) = -50 -15(3) = -95
The first term of the arithmetic sequence is -65, so that is g(1). Each next term is 15 less than the one before, so the recursive formula is ...
g(n) = g(n-1) -15
The complete recursive function definition requires both parts:
g(1) = -65
g(n) = g(n-1) -15
The area of a circle is pi*r^2 so 324/pi is 103 if you take the square root of that it is 10.15. so you would use the circumference formula now, which is 2 pi r so 2*pi*10.15= 63.77
Answer:
i think 30
Step-by-step explanation:
the best choice
To graph an equation with one x variable you first go on the y (vertical axis) and put a point at the number that doesnt have the x (12). Sometimes this number could be zero. The +12 is where it crosses the y axis. next to make the line you look at the number infront of x (1). that is the slope. It is basically 1 over 1. this means you go up one and right one, up one and right one, or down one and left one etc. this will make a line. If the number infront of x was -2 then it is seen as -2 over one. this slope is drawn by going down one and right one or up two and left one
