Choose Yes or No to tell if each equation is true.

Carlo think he will go to the gym about 20 times a month.Calculate how much each of these options would cost carlo for one month

galben [10]

20 divided by 4 is 5 so

4$ will be for pay as you go.

5$ will be for regular deal

4+5=9 so the all in one deal is 9$

3 0

2 years ago

For what values of x is the quantity x−9 negative?

Contact [7]

X - 9 < 0
add 9 to both sides:-
x - 9 + 9 < 9
x < 9

x - 9 is negative for all values of x less that 9.

6 0

3 years ago

Simplify (3a ^2)^ 3

Leya [2.2K]

The answer is 27a^6
Hope this helps.

7 0

3 years ago

It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the

son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that $p = 0.5$

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039$

$P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313$

$P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094$

$P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188$

$P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734$

$P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188$

$P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556$

85.56% probability that less than 6 of them have a high school diploma

7 0

3 years ago

It would be amazing if u helped me with the question below, thx! <3

tekilochka [14]

namely, how many times does 4 x 10⁻³ go into 8 x 10⁶.

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\a^{-n} \implies \cfrac{1}{a^n}\qquad \qquad\cfrac{1}{a^n}\implies a^{-n}\qquad \qquad a^n\implies \cfrac{1}{a^{-n}}\\\\-------------------------------\\\\\cfrac{\stackrel{elephant}{8\times 10^6}}{\stackrel{ant}{4\times 10^{-3}}}\implies \cfrac{8}{4}\times \cfrac{10^6}{10^{-3}}\implies 2\times 10^6\cdot 10^3\\\\\\2\times 10^{6+3}\implies 2.0\times 10^9$

7 0

3 years ago